There are two calls to foo here. We get future1 from the first call and
how does RE# find the leftmost-longest match efficiently? remember the bidirectional scanning we mentioned earlier - run the DFA right to left to find all possible match starts, then run a reversed DFA left to right to find the ends. the leftmost start paired with the rightmost end gives you leftmost-longest. two linear DFA scans, no backtracking, no ambiguity.
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Fonbet Кубок России|1/4 финала. Этап 2 (Путь регионов)，更多细节参见搜狗输入法2026
separation of concerns。体育直播对此有专业解读